Base | Representation |
---|---|
bin | 11010100101101101111001… |
… | …011000000010110111010001 |
3 | 120100001110110002022020222002 |
4 | 122211231321120002313101 |
5 | 110311430343343231023 |
6 | 1052414001003523345 |
7 | 33426500513024144 |
oct | 3245557130026721 |
9 | 510043402266862 |
10 | 116941110914513 |
11 | 342964a050aa46 |
12 | 11147b79529555 |
13 | 5033665372472 |
14 | 20c3da106405b |
15 | d7bd8ee9db28 |
hex | 6a5b79602dd1 |
116941110914513 has 2 divisors, whose sum is σ = 116941110914514. Its totient is φ = 116941110914512.
The previous prime is 116941110914489. The next prime is 116941110914521. The reversal of 116941110914513 is 315419011149611.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 116790017005249 + 151093909264 = 10806943^2 + 388708^2 .
It is a cyclic number.
It is not a de Polignac number, because 116941110914513 - 228 = 116940842479057 is a prime.
It is not a weakly prime, because it can be changed into another prime (116941110914543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58470555457256 + 58470555457257.
It is an arithmetic number, because the mean of its divisors is an integer number (58470555457257).
Almost surely, 2116941110914513 is an apocalyptic number.
It is an amenable number.
116941110914513 is a deficient number, since it is larger than the sum of its proper divisors (1).
116941110914513 is an equidigital number, since it uses as much as digits as its factorization.
116941110914513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 116640, while the sum is 47.
The spelling of 116941110914513 in words is "one hundred sixteen trillion, nine hundred forty-one billion, one hundred ten million, nine hundred fourteen thousand, five hundred thirteen".
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