Base | Representation |
---|---|
bin | 11010100101101101111001… |
… | …011000000010110111101111 |
3 | 120100001110110002022021000012 |
4 | 122211231321120002313233 |
5 | 110311430343343231133 |
6 | 1052414001003523435 |
7 | 33426500513024216 |
oct | 3245557130026757 |
9 | 510043402267005 |
10 | 116941110914543 |
11 | 342964a050aa73 |
12 | 11147b7952957b |
13 | 5033665372496 |
14 | 20c3da106407d |
15 | d7bd8ee9db48 |
hex | 6a5b79602def |
116941110914543 has 2 divisors, whose sum is σ = 116941110914544. Its totient is φ = 116941110914542.
The previous prime is 116941110914531. The next prime is 116941110914569. The reversal of 116941110914543 is 345419011149611.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 116941110914543 - 24 = 116941110914527 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 116941110914491 and 116941110914500.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (116941110914513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58470555457271 + 58470555457272.
It is an arithmetic number, because the mean of its divisors is an integer number (58470555457272).
Almost surely, 2116941110914543 is an apocalyptic number.
116941110914543 is a deficient number, since it is larger than the sum of its proper divisors (1).
116941110914543 is an equidigital number, since it uses as much as digits as its factorization.
116941110914543 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 466560, while the sum is 50.
The spelling of 116941110914543 in words is "one hundred sixteen trillion, nine hundred forty-one billion, one hundred ten million, nine hundred fourteen thousand, five hundred forty-three".
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