Base | Representation |
---|---|
bin | 11010100110100100110011… |
… | …111100101010100000111101 |
3 | 120100021002122102212020100011 |
4 | 122212210303330222200331 |
5 | 110313412123331314013 |
6 | 1052501032010503221 |
7 | 33433655642021233 |
oct | 3246446374524075 |
9 | 510232572766304 |
10 | 117000075651133 |
11 | 343094a9579334 |
12 | 11157494734b11 |
13 | 50390a149686c |
14 | 20c6b9622a953 |
15 | d7d6918a6c3d |
hex | 6a6933f2a83d |
117000075651133 has 2 divisors, whose sum is σ = 117000075651134. Its totient is φ = 117000075651132.
The previous prime is 117000075651127. The next prime is 117000075651211. The reversal of 117000075651133 is 331156570000711.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 106999535907364 + 10000539743769 = 10344058^2 + 3162363^2 .
It is a cyclic number.
It is not a de Polignac number, because 117000075651133 - 229 = 116999538780221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (117000075657133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58500037825566 + 58500037825567.
It is an arithmetic number, because the mean of its divisors is an integer number (58500037825567).
Almost surely, 2117000075651133 is an apocalyptic number.
It is an amenable number.
117000075651133 is a deficient number, since it is larger than the sum of its proper divisors (1).
117000075651133 is an equidigital number, since it uses as much as digits as its factorization.
117000075651133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 66150, while the sum is 40.
The spelling of 117000075651133 in words is "one hundred seventeen trillion, seventy-five million, six hundred fifty-one thousand, one hundred thirty-three".
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