11700210743941 has 2 divisors, whose sum is σ = 11700210743942. Its totient is φ = 11700210743940.

The previous prime is 11700210743909. The next prime is 11700210743951. The reversal of 11700210743941 is 14934701200711.

11700210743941 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10281065088100 + 1419145655841 = 3206410^2 + 1191279^2 .

It is a cyclic number.

It is not a de Polignac number, because 11700210743941 - 2⁵ = 11700210743909 is a prime.

It is a super-2 number, since 2×11700210743941² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11700210743894 and 11700210743903.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11700210743951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5850105371970 + 5850105371971.

It is an arithmetic number, because the mean of its divisors is an integer number (5850105371971).

Almost surely, 2^{11700210743941} is an apocalyptic number.

It is an amenable number.

11700210743941 is a deficient number, since it is larger than the sum of its proper divisors (1).

11700210743941 is an equidigital number, since it uses as much as digits as its factorization.

11700210743941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 42336, while the sum is 40.

The spelling of 11700210743941 in words is "eleven trillion, seven hundred billion, two hundred ten million, seven hundred forty-three thousand, nine hundred forty-one".