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11700262722143 is a prime number
BaseRepresentation
bin1010101001000010111000…
…0000001101101001011111
31112102112102102111202002002
42222100232000031221133
53013144114224102033
640515005415552515
72315213263126532
oct252205600155137
945375372452062
1011700262722143
113801065310646
12138b70a38b73b
1366b43a139288
142c641d708a19
1515453d85a3e8
hexaa42e00da5f

11700262722143 has 2 divisors, whose sum is σ = 11700262722144. Its totient is φ = 11700262722142.

The previous prime is 11700262722121. The next prime is 11700262722151. The reversal of 11700262722143 is 34122726200711.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11700262722143 - 28 = 11700262721887 is a prime.

It is a super-2 number, since 2×117002627221432 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11700262722097 and 11700262722106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11700262727143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5850131361071 + 5850131361072.

It is an arithmetic number, because the mean of its divisors is an integer number (5850131361072).

Almost surely, 211700262722143 is an apocalyptic number.

11700262722143 is a deficient number, since it is larger than the sum of its proper divisors (1).

11700262722143 is an equidigital number, since it uses as much as digits as its factorization.

11700262722143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56448, while the sum is 38.

Adding to 11700262722143 its reverse (34122726200711), we get a palindrome (45822988922854).

The spelling of 11700262722143 in words is "eleven trillion, seven hundred billion, two hundred sixty-two million, seven hundred twenty-two thousand, one hundred forty-three".