Base | Representation |
---|---|
bin | 110110100000011101… |
… | …0010011000010010010 |
3 | 102012010122010200002122 |
4 | 1231000322103002102 |
5 | 3404211101004023 |
6 | 125435023014242 |
7 | 11312454166103 |
oct | 1550072230222 |
9 | 365118120078 |
10 | 117053141138 |
11 | 457074a047a |
12 | 1a828a3a382 |
13 | b06581abbb |
14 | 5945c143aa |
15 | 30a140c2c8 |
hex | 1b40e93092 |
117053141138 has 16 divisors (see below), whose sum is σ = 183234229056. Its totient is φ = 55975637520.
The previous prime is 117053141129. The next prime is 117053141143. The reversal of 117053141138 is 831141350711.
It is a junction number, because it is equal to n+sod(n) for n = 117053141098 and 117053141107.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 283745 + ... + 560907.
It is an arithmetic number, because the mean of its divisors is an integer number (11452139316).
Almost surely, 2117053141138 is an apocalyptic number.
117053141138 is a deficient number, since it is larger than the sum of its proper divisors (66181087918).
117053141138 is a wasteful number, since it uses less digits than its factorization.
117053141138 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 286369.
The product of its (nonzero) digits is 10080, while the sum is 35.
Adding to 117053141138 its reverse (831141350711), we get a palindrome (948194491849).
The spelling of 117053141138 in words is "one hundred seventeen billion, fifty-three million, one hundred forty-one thousand, one hundred thirty-eight".
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