Base | Representation |
---|---|
bin | 110110100000011101… |
… | …0010011000010010111 |
3 | 102012010122010200002211 |
4 | 1231000322103002113 |
5 | 3404211101004033 |
6 | 125435023014251 |
7 | 11312454166111 |
oct | 1550072230227 |
9 | 365118120084 |
10 | 117053141143 |
11 | 457074a0484 |
12 | 1a828a3a387 |
13 | b06581abc3 |
14 | 5945c143b1 |
15 | 30a140c2cd |
hex | 1b40e93097 |
117053141143 has 2 divisors, whose sum is σ = 117053141144. Its totient is φ = 117053141142.
The previous prime is 117053141129. The next prime is 117053141197. The reversal of 117053141143 is 341141350711.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 117053141143 - 25 = 117053141111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (117053141123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58526570571 + 58526570572.
It is an arithmetic number, because the mean of its divisors is an integer number (58526570572).
Almost surely, 2117053141143 is an apocalyptic number.
117053141143 is a deficient number, since it is larger than the sum of its proper divisors (1).
117053141143 is an equidigital number, since it uses as much as digits as its factorization.
117053141143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 31.
Adding to 117053141143 its reverse (341141350711), we get a palindrome (458194491854).
The spelling of 117053141143 in words is "one hundred seventeen billion, fifty-three million, one hundred forty-one thousand, one hundred forty-three".
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