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11706774133 = 19616146007
BaseRepresentation
bin10101110011100011…
…10011001001110101
31010012212100202002011
422321301303021311
5142433413233013
65213352444221
7563050636555
oct127161631165
933185322064
1011706774133
114a6819474a
1223286a9671
1311474991b2
147d0acd165
15487b4dc3d
hex2b9c73275

11706774133 has 4 divisors (see below), whose sum is σ = 12322920160. Its totient is φ = 11090628108.

The previous prime is 11706774113. The next prime is 11706774139. The reversal of 11706774133 is 33147760711.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11706774133 - 229 = 11169903221 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11706774139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 308072985 + ... + 308073022.

It is an arithmetic number, because the mean of its divisors is an integer number (3080730040).

Almost surely, 211706774133 is an apocalyptic number.

It is an amenable number.

11706774133 is a deficient number, since it is larger than the sum of its proper divisors (616146027).

11706774133 is an equidigital number, since it uses as much as digits as its factorization.

11706774133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 616146026.

The product of its (nonzero) digits is 74088, while the sum is 40.

The spelling of 11706774133 in words is "eleven billion, seven hundred six million, seven hundred seventy-four thousand, one hundred thirty-three".

Divisors: 1 19 616146007 11706774133