Base | Representation |
---|---|
bin | 10101110100000101… |
… | …11000111000001110 |
3 | 1010020011210100100021 |
4 | 22322002320320032 |
5 | 142441040112110 |
6 | 5214032452354 |
7 | 563134005520 |
oct | 127202707016 |
9 | 33204710307 |
10 | 11711254030 |
11 | 4a6a774543 |
12 | 232a0aa0ba |
13 | 11483a7318 |
14 | 7d1537a10 |
15 | 4882362da |
hex | 2ba0b8e0e |
11711254030 has 64 divisors (see below), whose sum is σ = 24358942080. Its totient is φ = 3971003904.
The previous prime is 11711254019. The next prime is 11711254033. The reversal of 11711254030 is 3045211711.
It is a junction number, because it is equal to n+sod(n) for n = 11711253986 and 11711254004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11711254033) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2383216 + ... + 2388124.
It is an arithmetic number, because the mean of its divisors is an integer number (380608470).
Almost surely, 211711254030 is an apocalyptic number.
11711254030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11711254030 is an abundant number, since it is smaller than the sum of its proper divisors (12647688050).
11711254030 is a wasteful number, since it uses less digits than its factorization.
11711254030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5293.
The product of its (nonzero) digits is 840, while the sum is 25.
Adding to 11711254030 its reverse (3045211711), we get a palindrome (14756465741).
The spelling of 11711254030 in words is "eleven billion, seven hundred eleven million, two hundred fifty-four thousand, thirty".
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