Search a number
-
+
1171270306741 is a prime number
BaseRepresentation
bin10001000010110101001…
…001101000101110110101
311010222020211201110212011
4101002311021220232311
5123142230144303431
62254024003324221
7150423112224253
oct21026511505665
94128224643764
101171270306741
1141180760a347
1216b000080671
13865b1462402
1440992ab15d3
1520702888cb1
hex110b5268bb5

1171270306741 has 2 divisors, whose sum is σ = 1171270306742. Its totient is φ = 1171270306740.

The previous prime is 1171270306673. The next prime is 1171270306747. The reversal of 1171270306741 is 1476030721711.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 939833302500 + 231437004241 = 969450^2 + 481079^2 .

It is a cyclic number.

It is not a de Polignac number, because 1171270306741 - 233 = 1162680372149 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1171270306694 and 1171270306703.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1171270306747) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 585635153370 + 585635153371.

It is an arithmetic number, because the mean of its divisors is an integer number (585635153371).

Almost surely, 21171270306741 is an apocalyptic number.

It is an amenable number.

1171270306741 is a deficient number, since it is larger than the sum of its proper divisors (1).

1171270306741 is an equidigital number, since it uses as much as digits as its factorization.

1171270306741 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 49392, while the sum is 40.

The spelling of 1171270306741 in words is "one trillion, one hundred seventy-one billion, two hundred seventy million, three hundred six thousand, seven hundred forty-one".