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1171413053693 is a prime number
BaseRepresentation
bin10001000010111101101…
…010001011000011111101
311010222121210022202212022
4101002331222023003331
5123143023220204233
62254050103045525
7150426464445161
oct21027552130375
94128553282768
101171413053693
11411880148233
1216b03ba408a5
1386604bc1b6c
14409a7a2cca1
1520710184398
hex110bda8b0fd

1171413053693 has 2 divisors, whose sum is σ = 1171413053694. Its totient is φ = 1171413053692.

The previous prime is 1171413053639. The next prime is 1171413053771. The reversal of 1171413053693 is 3963503141711.

Together with previous prime (1171413053639) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1088343438169 + 83069615524 = 1043237^2 + 288218^2 .

It is an emirp because it is prime and its reverse (3963503141711) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1171413053693 - 220 = 1171412005117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1171413050693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 585706526846 + 585706526847.

It is an arithmetic number, because the mean of its divisors is an integer number (585706526847).

Almost surely, 21171413053693 is an apocalyptic number.

It is an amenable number.

1171413053693 is a deficient number, since it is larger than the sum of its proper divisors (1).

1171413053693 is an equidigital number, since it uses as much as digits as its factorization.

1171413053693 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 204120, while the sum is 44.

The spelling of 1171413053693 in words is "one trillion, one hundred seventy-one billion, four hundred thirteen million, fifty-three thousand, six hundred ninety-three".