Base | Representation |
---|---|
bin | 110110100100010011… |
… | …0111011110110001111 |
3 | 102012110122010202122011 |
4 | 1231020212323312033 |
5 | 3404442131030101 |
6 | 125455515002051 |
7 | 11315612654323 |
oct | 1551046736617 |
9 | 365418122564 |
10 | 117182283151 |
11 | 4577338680a |
12 | 1a864139327 |
13 | b0864c5cab |
14 | 595902d983 |
15 | 30ac91b751 |
hex | 1b489bbd8f |
117182283151 has 2 divisors, whose sum is σ = 117182283152. Its totient is φ = 117182283150.
The previous prime is 117182283139. The next prime is 117182283193. The reversal of 117182283151 is 151382281711.
It is a weak prime.
It is an emirp because it is prime and its reverse (151382281711) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 117182283151 - 29 = 117182282639 is a prime.
It is a super-2 number, since 2×1171822831512 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (117182283851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58591141575 + 58591141576.
It is an arithmetic number, because the mean of its divisors is an integer number (58591141576).
Almost surely, 2117182283151 is an apocalyptic number.
117182283151 is a deficient number, since it is larger than the sum of its proper divisors (1).
117182283151 is an equidigital number, since it uses as much as digits as its factorization.
117182283151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 26880, while the sum is 40.
The spelling of 117182283151 in words is "one hundred seventeen billion, one hundred eighty-two million, two hundred eighty-three thousand, one hundred fifty-one".
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