Base | Representation |
---|---|
bin | 100010111011101… |
… | …0101100101101101 |
3 | 10000200120120220202 |
4 | 1011313111211231 |
5 | 4400031244003 |
6 | 312150523245 |
7 | 41021656013 |
oct | 10567254555 |
9 | 3020516822 |
10 | 1172134253 |
11 | 5517038a4 |
12 | 288666525 |
13 | 158ab8a84 |
14 | b19588b3 |
15 | 6cd84088 |
hex | 45dd596d |
1172134253 has 2 divisors, whose sum is σ = 1172134254. Its totient is φ = 1172134252.
The previous prime is 1172134213. The next prime is 1172134321. The reversal of 1172134253 is 3524312711.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 608214244 + 563920009 = 24662^2 + 23747^2 .
It is an emirp because it is prime and its reverse (3524312711) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1172134253 - 218 = 1171872109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1172134213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 586067126 + 586067127.
It is an arithmetic number, because the mean of its divisors is an integer number (586067127).
Almost surely, 21172134253 is an apocalyptic number.
It is an amenable number.
1172134253 is a deficient number, since it is larger than the sum of its proper divisors (1).
1172134253 is an equidigital number, since it uses as much as digits as its factorization.
1172134253 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5040, while the sum is 29.
The square root of 1172134253 is about 34236.4462670996. The cubic root of 1172134253 is about 1054.3685725431.
Adding to 1172134253 its reverse (3524312711), we get a palindrome (4696446964).
The spelling of 1172134253 in words is "one billion, one hundred seventy-two million, one hundred thirty-four thousand, two hundred fifty-three".
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