Base | Representation |
---|---|
bin | 10101110101011111… |
… | …11001110000111101 |
3 | 1010020222222212001102 |
4 | 22322233321300331 |
5 | 143002100213031 |
6 | 5215133422445 |
7 | 563336213261 |
oct | 127257716075 |
9 | 33228885042 |
10 | 11723054141 |
11 | 4a763a40a7 |
12 | 233203aa25 |
13 | 114a979336 |
14 | 7d2d2a0a1 |
15 | 4892b77cb |
hex | 2babf9c3d |
11723054141 has 4 divisors (see below), whose sum is σ = 11807392800. Its totient is φ = 11638715484.
The previous prime is 11723054113. The next prime is 11723054171. The reversal of 11723054141 is 14145032711.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11723054141 - 210 = 11723053117 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11723054171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42169121 + ... + 42169398.
It is an arithmetic number, because the mean of its divisors is an integer number (2951848200).
Almost surely, 211723054141 is an apocalyptic number.
It is an amenable number.
11723054141 is a deficient number, since it is larger than the sum of its proper divisors (84338659).
11723054141 is an equidigital number, since it uses as much as digits as its factorization.
11723054141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84338658.
The product of its (nonzero) digits is 3360, while the sum is 29.
Adding to 11723054141 its reverse (14145032711), we get a palindrome (25868086852).
The spelling of 11723054141 in words is "eleven billion, seven hundred twenty-three million, fifty-four thousand, one hundred forty-one".
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