Base | Representation |
---|---|
bin | 110110100110000111… |
… | …1010110101101110101 |
3 | 102012121212210012101211 |
4 | 1231030033112231311 |
5 | 3410103230214423 |
6 | 125505532521421 |
7 | 11320252563364 |
oct | 1551417265565 |
9 | 365555705354 |
10 | 117243210613 |
11 | 457a4810491 |
12 | 1a880620271 |
13 | b096009149 |
14 | 596316d7db |
15 | 30b2e5410d |
hex | 1b4c3d6b75 |
117243210613 has 4 divisors (see below), whose sum is σ = 117481995648. Its totient is φ = 117004425580.
The previous prime is 117243210607. The next prime is 117243210647. The reversal of 117243210613 is 316012342711.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-117243210613 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (117243210013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119391781 + ... + 119392762.
It is an arithmetic number, because the mean of its divisors is an integer number (29370498912).
Almost surely, 2117243210613 is an apocalyptic number.
It is an amenable number.
117243210613 is a deficient number, since it is larger than the sum of its proper divisors (238785035).
117243210613 is an equidigital number, since it uses as much as digits as its factorization.
117243210613 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 238785034.
The product of its (nonzero) digits is 6048, while the sum is 31.
The spelling of 117243210613 in words is "one hundred seventeen billion, two hundred forty-three million, two hundred ten thousand, six hundred thirteen".
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