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117250060672981 is a prime number
BaseRepresentation
bin11010101010001101101000…
…001101110101111111010101
3120101010222220022210010022001
4122222031220031311333111
5110332011111013013411
61053211533445235301
733461015543446015
oct3252155015657725
9511128808703261
10117250060672981
11343a5520602245
1211197a20102b31
135056830410032
1420d4d0ca5dc45
15d84e23212dc1
hex6aa368375fd5

117250060672981 has 2 divisors, whose sum is σ = 117250060672982. Its totient is φ = 117250060672980.

The previous prime is 117250060672909. The next prime is 117250060673033. The reversal of 117250060672981 is 189276060052711.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70207389630225 + 47042671042756 = 8378985^2 + 6858766^2 .

It is a cyclic number.

It is not a de Polignac number, because 117250060672981 - 227 = 117249926455253 is a prime.

It is a super-2 number, since 2×1172500606729812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (117250060676981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58625030336490 + 58625030336491.

It is an arithmetic number, because the mean of its divisors is an integer number (58625030336491).

Almost surely, 2117250060672981 is an apocalyptic number.

It is an amenable number.

117250060672981 is a deficient number, since it is larger than the sum of its proper divisors (1).

117250060672981 is an equidigital number, since it uses as much as digits as its factorization.

117250060672981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2540160, while the sum is 55.

The spelling of 117250060672981 in words is "one hundred seventeen trillion, two hundred fifty billion, sixty million, six hundred seventy-two thousand, nine hundred eighty-one".