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11726470326673 is a prime number
BaseRepresentation
bin1010101010100100100000…
…0110010010100110010001
31112112001001212201222212201
42222221020012102212101
53014111302400423143
640535022135523201
72320131603111034
oct252511006224621
945461055658781
1011726470326673
113811193877843
121394803229501
13670a558ca38b
142c77c820101b
1515507456b64d
hexaaa48192991

11726470326673 has 2 divisors, whose sum is σ = 11726470326674. Its totient is φ = 11726470326672.

The previous prime is 11726470326647. The next prime is 11726470326749. The reversal of 11726470326673 is 37662307462711.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6117000188049 + 5609470138624 = 2473257^2 + 2368432^2 .

It is an emirp because it is prime and its reverse (37662307462711) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11726470326673 - 237 = 11589031373201 is a prime.

It is not a weakly prime, because it can be changed into another prime (11726470320673) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5863235163336 + 5863235163337.

It is an arithmetic number, because the mean of its divisors is an integer number (5863235163337).

Almost surely, 211726470326673 is an apocalyptic number.

It is an amenable number.

11726470326673 is a deficient number, since it is larger than the sum of its proper divisors (1).

11726470326673 is an equidigital number, since it uses as much as digits as its factorization.

11726470326673 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10668672, while the sum is 55.

The spelling of 11726470326673 in words is "eleven trillion, seven hundred twenty-six billion, four hundred seventy million, three hundred twenty-six thousand, six hundred seventy-three".