Base | Representation |
---|---|
bin | 1010101010101011000100… |
… | …1111111110000101110111 |
3 | 1112112012121211021212001002 |
4 | 2222222301033332011313 |
5 | 3014123411011044144 |
6 | 40535513155353515 |
7 | 2320223404103216 |
oct | 252526117760567 |
9 | 45465554255032 |
10 | 11728234471799 |
11 | 3811a0967211a |
12 | 1395015bb289b |
13 | 670c77245531 |
14 | 2c791462307d |
15 | 15512939114e |
hex | aaab13fe177 |
11728234471799 has 2 divisors, whose sum is σ = 11728234471800. Its totient is φ = 11728234471798.
The previous prime is 11728234471787. The next prime is 11728234471853. The reversal of 11728234471799 is 99717443282711.
It is a weak prime.
It is an emirp because it is prime and its reverse (99717443282711) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11728234471799 - 216 = 11728234406263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11028234471799) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5864117235899 + 5864117235900.
It is an arithmetic number, because the mean of its divisors is an integer number (5864117235900).
Almost surely, 211728234471799 is an apocalyptic number.
11728234471799 is a deficient number, since it is larger than the sum of its proper divisors (1).
11728234471799 is an equidigital number, since it uses as much as digits as its factorization.
11728234471799 is an evil number, because the sum of its binary digits is even.
The product of its digits is 42674688, while the sum is 65.
The spelling of 11728234471799 in words is "eleven trillion, seven hundred twenty-eight billion, two hundred thirty-four million, four hundred seventy-one thousand, seven hundred ninety-nine".
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