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117375840410701 is a prime number
BaseRepresentation
bin11010101100000010110001…
…010001011101110001001101
3120101121000120010112211102111
4122230002301101131301031
5110341041210121120301
61053345414445424021
733503060513541505
oct3254026121356115
9511530503484374
10117375840410701
11344438a5a25904
12111b828356b011
135065656b63242
1420db04183aa05
15d883357e3551
hex6ac0b145dc4d

117375840410701 has 2 divisors, whose sum is σ = 117375840410702. Its totient is φ = 117375840410700.

The previous prime is 117375840410677. The next prime is 117375840410747. The reversal of 117375840410701 is 107014048573711.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94698491629225 + 22677348781476 = 9731315^2 + 4762074^2 .

It is a cyclic number.

It is not a de Polignac number, because 117375840410701 - 215 = 117375840377933 is a prime.

It is a super-2 number, since 2×1173758404107012 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (117375840410201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58687920205350 + 58687920205351.

It is an arithmetic number, because the mean of its divisors is an integer number (58687920205351).

Almost surely, 2117375840410701 is an apocalyptic number.

It is an amenable number.

117375840410701 is a deficient number, since it is larger than the sum of its proper divisors (1).

117375840410701 is an equidigital number, since it uses as much as digits as its factorization.

117375840410701 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 658560, while the sum is 49.

The spelling of 117375840410701 in words is "one hundred seventeen trillion, three hundred seventy-five billion, eight hundred forty million, four hundred ten thousand, seven hundred one".