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11740039981 is a prime number
BaseRepresentation
bin10101110111100001…
…01100101100101101
31010022011221211020121
422323300230230231
5143020422234411
65220541444541
7563633456545
oct127360545455
933264854217
1011740039981
114a84a4588a
122337870751
131151345827
147d52ac325
1548aa20571
hex2bbc2cb2d

11740039981 has 2 divisors, whose sum is σ = 11740039982. Its totient is φ = 11740039980.

The previous prime is 11740039973. The next prime is 11740040003. The reversal of 11740039981 is 18993004711.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7440615081 + 4299424900 = 86259^2 + 65570^2 .

It is an emirp because it is prime and its reverse (18993004711) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11740039981 - 23 = 11740039973 is a prime.

It is a super-2 number, since 2×117400399812 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11740039951) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5870019990 + 5870019991.

It is an arithmetic number, because the mean of its divisors is an integer number (5870019991).

Almost surely, 211740039981 is an apocalyptic number.

It is an amenable number.

11740039981 is a deficient number, since it is larger than the sum of its proper divisors (1).

11740039981 is an equidigital number, since it uses as much as digits as its factorization.

11740039981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54432, while the sum is 43.

The spelling of 11740039981 in words is "eleven billion, seven hundred forty million, thirty-nine thousand, nine hundred eighty-one".