Base | Representation |
---|---|
bin | 110110101101011000… |
… | …1110101101001100111 |
3 | 102020020212202122121002 |
4 | 1231122301311221213 |
5 | 3411103201144424 |
6 | 125550044543515 |
7 | 11326304065262 |
oct | 1553261655147 |
9 | 366225678532 |
10 | 117487131239 |
11 | 4590a471685 |
12 | 1a92a251b9b |
13 | b10470068a |
14 | 5987705cd9 |
15 | 30c9586cae |
hex | 1b5ac75a67 |
117487131239 has 4 divisors (see below), whose sum is σ = 117541957056. Its totient is φ = 117432305424.
The previous prime is 117487131221. The next prime is 117487131247. The reversal of 117487131239 is 932131784711.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 932131784711 = 113 ⋅8248953847.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-117487131239 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 117487131193 and 117487131202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (117487131299) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27409694 + ... + 27413979.
It is an arithmetic number, because the mean of its divisors is an integer number (29385489264).
Almost surely, 2117487131239 is an apocalyptic number.
117487131239 is a deficient number, since it is larger than the sum of its proper divisors (54825817).
117487131239 is an equidigital number, since it uses as much as digits as its factorization.
117487131239 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54825816.
The product of its digits is 254016, while the sum is 47.
The spelling of 117487131239 in words is "one hundred seventeen billion, four hundred eighty-seven million, one hundred thirty-one thousand, two hundred thirty-nine".
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