Base | Representation |
---|---|
bin | 10101111001000101… |
… | …01001000001110001 |
3 | 1010100002120222022120 |
4 | 22330202221001301 |
5 | 143032300212040 |
6 | 5222130224453 |
7 | 564152655246 |
oct | 127442510161 |
9 | 33302528276 |
10 | 11753132145 |
11 | 4a91378157 |
12 | 2340125129 |
13 | 1153c7a981 |
14 | 7d6d195cd |
15 | 48bc597d0 |
hex | 2bc8a9071 |
11753132145 has 32 divisors (see below), whose sum is σ = 19603897344. Its totient is φ = 6006048000.
The previous prime is 11753132123. The next prime is 11753132173. The reversal of 11753132145 is 54123135711.
It is not a de Polignac number, because 11753132145 - 25 = 11753132113 is a prime.
It is a super-2 number, since 2×117531321452 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 78162 + ... + 172091.
It is an arithmetic number, because the mean of its divisors is an integer number (612621792).
Almost surely, 211753132145 is an apocalyptic number.
11753132145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11753132145 is a deficient number, since it is larger than the sum of its proper divisors (7850765199).
11753132145 is a wasteful number, since it uses less digits than its factorization.
11753132145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 250393.
The product of its digits is 12600, while the sum is 33.
Adding to 11753132145 its reverse (54123135711), we get a palindrome (65876267856).
The spelling of 11753132145 in words is "eleven billion, seven hundred fifty-three million, one hundred thirty-two thousand, one hundred forty-five".
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