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11756849057 is a prime number
BaseRepresentation
bin10101111001100001…
…10100011110100001
31010100100120210221222
422330300310132201
5143034223132212
65222342024425
7564226365602
oct127460643641
933310523858
1011756849057
114a93486788
122341418115
13115497c725
147d7605da9
1548c240c72
hex2bcc347a1

11756849057 has 2 divisors, whose sum is σ = 11756849058. Its totient is φ = 11756849056.

The previous prime is 11756849029. The next prime is 11756849077. The reversal of 11756849057 is 75094865711.

11756849057 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6203767696 + 5553081361 = 78764^2 + 74519^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11756849057 is a prime.

It is not a weakly prime, because it can be changed into another prime (11756849077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5878424528 + 5878424529.

It is an arithmetic number, because the mean of its divisors is an integer number (5878424529).

Almost surely, 211756849057 is an apocalyptic number.

It is an amenable number.

11756849057 is a deficient number, since it is larger than the sum of its proper divisors (1).

11756849057 is an equidigital number, since it uses as much as digits as its factorization.

11756849057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2116800, while the sum is 53.

The spelling of 11756849057 in words is "eleven billion, seven hundred fifty-six million, eight hundred forty-nine thousand, fifty-seven".