Base | Representation |
---|---|
bin | 10101111010011111… |
… | …01111000101111111 |
3 | 1010100220211120010110 |
4 | 22331033233011333 |
5 | 143043312002341 |
6 | 5223231441103 |
7 | 564355311615 |
oct | 127517570577 |
9 | 33326746113 |
10 | 11764953471 |
11 | 4a98011747 |
12 | 2344086193 |
13 | 115655953b |
14 | 7d87156b5 |
15 | 48cce2216 |
hex | 2bd3ef17f |
11764953471 has 4 divisors (see below), whose sum is σ = 15686604632. Its totient is φ = 7843302312.
The previous prime is 11764953457. The next prime is 11764953509. The reversal of 11764953471 is 17435946711.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 11764953471 - 213 = 11764945279 is a prime.
It is a super-3 number, since 3×117649534713 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11764953471.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11764953371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1960825576 + ... + 1960825581.
It is an arithmetic number, because the mean of its divisors is an integer number (3921651158).
Almost surely, 211764953471 is an apocalyptic number.
11764953471 is a deficient number, since it is larger than the sum of its proper divisors (3921651161).
11764953471 is an equidigital number, since it uses as much as digits as its factorization.
11764953471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3921651160.
The product of its digits is 635040, while the sum is 48.
The spelling of 11764953471 in words is "eleven billion, seven hundred sixty-four million, nine hundred fifty-three thousand, four hundred seventy-one".
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