Base | Representation |
---|---|
bin | 110110110011001001… |
… | …1110101011000110101 |
3 | 102020202100210111110122 |
4 | 1231212103311120311 |
5 | 3412002212424222 |
6 | 130021155301325 |
7 | 11334143350142 |
oct | 1554623653065 |
9 | 366670714418 |
10 | 117680592437 |
11 | 459a9698971 |
12 | 1a982baa845 |
13 | b135808665 |
14 | 59a52a53c9 |
15 | 30db54da42 |
hex | 1b664f5635 |
117680592437 has 4 divisors (see below), whose sum is σ = 117681809856. Its totient is φ = 117679375020.
The previous prime is 117680592389. The next prime is 117680592493. The reversal of 117680592437 is 734295086711.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 117680592437 - 28 = 117680592181 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (117680595437) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 449903 + ... + 661644.
It is an arithmetic number, because the mean of its divisors is an integer number (29420452464).
It is a 1-persistent number, because it is pandigital, but 2⋅117680592437 = 235361184874 is not.
Almost surely, 2117680592437 is an apocalyptic number.
It is an amenable number.
117680592437 is a deficient number, since it is larger than the sum of its proper divisors (1217419).
117680592437 is a wasteful number, since it uses less digits than its factorization.
117680592437 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1217418.
The product of its (nonzero) digits is 2540160, while the sum is 53.
The spelling of 117680592437 in words is "one hundred seventeen billion, six hundred eighty million, five hundred ninety-two thousand, four hundred thirty-seven".
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