Base | Representation |
---|---|
bin | 10101111010111001… |
… | …10101111110100101 |
3 | 1010101011022010112022 |
4 | 22331130311332211 |
5 | 143100201431131 |
6 | 5223433232525 |
7 | 564426442406 |
oct | 127534657645 |
9 | 33334263468 |
10 | 11768389541 |
11 | 4a99a49277 |
12 | 2345262745 |
13 | 115719050c |
14 | 7d8d6b9ad |
15 | 48d27037b |
hex | 2bd735fa5 |
11768389541 has 2 divisors, whose sum is σ = 11768389542. Its totient is φ = 11768389540.
The previous prime is 11768389483. The next prime is 11768389579. The reversal of 11768389541 is 14598386711.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8552365441 + 3216024100 = 92479^2 + 56710^2 .
It is an emirp because it is prime and its reverse (14598386711) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11768389541 - 210 = 11768388517 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11768389441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5884194770 + 5884194771.
It is an arithmetic number, because the mean of its divisors is an integer number (5884194771).
Almost surely, 211768389541 is an apocalyptic number.
It is an amenable number.
11768389541 is a deficient number, since it is larger than the sum of its proper divisors (1).
11768389541 is an equidigital number, since it uses as much as digits as its factorization.
11768389541 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1451520, while the sum is 53.
The spelling of 11768389541 in words is "eleven billion, seven hundred sixty-eight million, three hundred eighty-nine thousand, five hundred forty-one".
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