Base | Representation |
---|---|
bin | 11010110000111101110001… |
… | …110100111010011000100011 |
3 | 120102210100121111221211112102 |
4 | 122300331301310322120203 |
5 | 110412111413031040012 |
6 | 1054205033455121015 |
7 | 33536363412040013 |
oct | 3260756164723043 |
9 | 512710544854472 |
10 | 117714078377507 |
11 | 34564295498567 |
12 | 1125193a81316b |
13 | 508b50b9885c1 |
14 | 210d56b117c43 |
15 | d9202ee302c2 |
hex | 6b0f71d3a623 |
117714078377507 has 2 divisors, whose sum is σ = 117714078377508. Its totient is φ = 117714078377506.
The previous prime is 117714078377431. The next prime is 117714078377509. The reversal of 117714078377507 is 705773870417711.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-117714078377507 is a prime.
It is a super-2 number, since 2×1177140783775072 (a number of 29 digits) contains 22 as substring.
Together with 117714078377509, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (117714078377509) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58857039188753 + 58857039188754.
It is an arithmetic number, because the mean of its divisors is an integer number (58857039188754).
Almost surely, 2117714078377507 is an apocalyptic number.
117714078377507 is a deficient number, since it is larger than the sum of its proper divisors (1).
117714078377507 is an equidigital number, since it uses as much as digits as its factorization.
117714078377507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56471520, while the sum is 65.
The spelling of 117714078377507 in words is "one hundred seventeen trillion, seven hundred fourteen billion, seventy-eight million, three hundred seventy-seven thousand, five hundred seven".
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