Base | Representation |
---|---|
bin | 1010101101010110011100… |
… | …0111010111110111010101 |
3 | 1112200121100201001022010011 |
4 | 2223111213013113313111 |
5 | 3020402113222004331 |
6 | 41013001542000221 |
7 | 2323442346055231 |
oct | 253254707276725 |
9 | 45617321038104 |
10 | 11774235344341 |
11 | 382a474997558 |
12 | 13a1b13716071 |
13 | 6753c860aa42 |
14 | 2c9c39b895c1 |
15 | 15641cad43b1 |
hex | ab5671d7dd5 |
11774235344341 has 2 divisors, whose sum is σ = 11774235344342. Its totient is φ = 11774235344340.
The previous prime is 11774235344321. The next prime is 11774235344351. The reversal of 11774235344341 is 14344353247711.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10282732488900 + 1491502855441 = 3206670^2 + 1221271^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11774235344341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11774235344321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5887117672170 + 5887117672171.
It is an arithmetic number, because the mean of its divisors is an integer number (5887117672171).
Almost surely, 211774235344341 is an apocalyptic number.
It is an amenable number.
11774235344341 is a deficient number, since it is larger than the sum of its proper divisors (1).
11774235344341 is an equidigital number, since it uses as much as digits as its factorization.
11774235344341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3386880, while the sum is 49.
The spelling of 11774235344341 in words is "eleven trillion, seven hundred seventy-four billion, two hundred thirty-five million, three hundred forty-four thousand, three hundred forty-one".
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