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11777015248387 is a prime number
BaseRepresentation
bin1010101101100000110011…
…0011110111011000000011
31112200212112102221001120021
42223120030303313120003
53020423311400422022
641014141444554311
72323601262624604
oct253301463673003
945625472831507
1011777015248387
113830671099614
1213a256a6b2997
1367574c51cc8c
142ca02105bdab
15156531b9e7c7
hexab60ccf7603

11777015248387 has 2 divisors, whose sum is σ = 11777015248388. Its totient is φ = 11777015248386.

The previous prime is 11777015248363. The next prime is 11777015248417. The reversal of 11777015248387 is 78384251077711.

11777015248387 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (78384251077711) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11777015248387 - 27 = 11777015248259 is a prime.

It is a super-2 number, since 2×117770152483872 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11777015248337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5888507624193 + 5888507624194.

It is an arithmetic number, because the mean of its divisors is an integer number (5888507624194).

Almost surely, 211777015248387 is an apocalyptic number.

11777015248387 is a deficient number, since it is larger than the sum of its proper divisors (1).

11777015248387 is an equidigital number, since it uses as much as digits as its factorization.

11777015248387 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18439680, while the sum is 61.

The spelling of 11777015248387 in words is "eleven trillion, seven hundred seventy-seven billion, fifteen million, two hundred forty-eight thousand, three hundred eighty-seven".