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11777015248417 is a prime number
BaseRepresentation
bin1010101101100000110011…
…0011110111011000100001
31112200212112102221001121101
42223120030303313120201
53020423311400422132
641014141444554401
72323601262624646
oct253301463673041
945625472831541
1011777015248417
113830671099641
1213a256a6b2a01
1367574c51ccb3
142ca02105bdcd
15156531b9e7e7
hexab60ccf7621

11777015248417 has 2 divisors, whose sum is σ = 11777015248418. Its totient is φ = 11777015248416.

The previous prime is 11777015248387. The next prime is 11777015248441. The reversal of 11777015248417 is 71484251077711.

11777015248417 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11563815114721 + 213200133696 = 3400561^2 + 461736^2 .

It is a cyclic number.

It is not a de Polignac number, because 11777015248417 - 227 = 11776881030689 is a prime.

It is a super-2 number, since 2×117770152484172 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11777015248477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5888507624208 + 5888507624209.

It is an arithmetic number, because the mean of its divisors is an integer number (5888507624209).

Almost surely, 211777015248417 is an apocalyptic number.

It is an amenable number.

11777015248417 is a deficient number, since it is larger than the sum of its proper divisors (1).

11777015248417 is an equidigital number, since it uses as much as digits as its factorization.

11777015248417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3073280, while the sum is 55.

The spelling of 11777015248417 in words is "eleven trillion, seven hundred seventy-seven billion, fifteen million, two hundred forty-eight thousand, four hundred seventeen".