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117811584013 is a prime number
BaseRepresentation
bin110110110111000011…
…1100001110000001101
3102021002111021120010111
41231232013201300031
53412234231142023
6130042155040021
711340323640604
oct1555607416015
9367074246114
10117811584013
1145a66627872
121a9baa40011
13b1569b0576
1459b8842a3b
1530e7cc600d
hex1b6e1e1c0d

117811584013 has 2 divisors, whose sum is σ = 117811584014. Its totient is φ = 117811584012.

The previous prime is 117811583993. The next prime is 117811584019. The reversal of 117811584013 is 310485118711.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115952508324 + 1859075689 = 340518^2 + 43117^2 .

It is a cyclic number.

It is not a de Polignac number, because 117811584013 - 29 = 117811583501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (117811584019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58905792006 + 58905792007.

It is an arithmetic number, because the mean of its divisors is an integer number (58905792007).

Almost surely, 2117811584013 is an apocalyptic number.

It is an amenable number.

117811584013 is a deficient number, since it is larger than the sum of its proper divisors (1).

117811584013 is an equidigital number, since it uses as much as digits as its factorization.

117811584013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26880, while the sum is 40.

The spelling of 117811584013 in words is "one hundred seventeen billion, eight hundred eleven million, five hundred eighty-four thousand, thirteen".