Base | Representation |
---|---|
bin | 110110111001101100… |
… | …1100110111100111111 |
3 | 102021022200001020002211 |
4 | 1231303121212330333 |
5 | 3412424423204413 |
6 | 130055042401251 |
7 | 11342451151423 |
oct | 1556331467477 |
9 | 367280036084 |
10 | 117900209983 |
11 | 4600165a876 |
12 | 1aa24660227 |
13 | b16c170c7a |
14 | 59c6512b83 |
15 | 310098083d |
hex | 1b73666f3f |
117900209983 has 2 divisors, whose sum is σ = 117900209984. Its totient is φ = 117900209982.
The previous prime is 117900209951. The next prime is 117900210013. The reversal of 117900209983 is 389902009711.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 117900209983 - 25 = 117900209951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (117900209923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58950104991 + 58950104992.
It is an arithmetic number, because the mean of its divisors is an integer number (58950104992).
Almost surely, 2117900209983 is an apocalyptic number.
117900209983 is a deficient number, since it is larger than the sum of its proper divisors (1).
117900209983 is an equidigital number, since it uses as much as digits as its factorization.
117900209983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 244944, while the sum is 49.
The spelling of 117900209983 in words is "one hundred seventeen billion, nine hundred million, two hundred nine thousand, nine hundred eighty-three".
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