Base | Representation |
---|---|
bin | 1010101110100001101000… |
… | …0000010101011000010111 |
3 | 1112202112110011102201111122 |
4 | 2223220122000111120113 |
5 | 3021214431110140012 |
6 | 41030140301554155 |
7 | 2325055431011504 |
oct | 253503200253027 |
9 | 45675404381448 |
10 | 11794416490007 |
11 | 3837a906a0a38 |
12 | 13a5a0627595b |
13 | 67729369ab58 |
14 | 2cabd21464ab |
15 | 156bee6d2e72 |
hex | aba1a015617 |
11794416490007 has 2 divisors, whose sum is σ = 11794416490008. Its totient is φ = 11794416490006.
The previous prime is 11794416489979. The next prime is 11794416490019. The reversal of 11794416490007 is 70009461449711.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11794416490007 - 210 = 11794416488983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11794416490037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5897208245003 + 5897208245004.
It is an arithmetic number, because the mean of its divisors is an integer number (5897208245004).
Almost surely, 211794416490007 is an apocalyptic number.
11794416490007 is a deficient number, since it is larger than the sum of its proper divisors (1).
11794416490007 is an equidigital number, since it uses as much as digits as its factorization.
11794416490007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1524096, while the sum is 53.
The spelling of 11794416490007 in words is "eleven trillion, seven hundred ninety-four billion, four hundred sixteen million, four hundred ninety thousand, seven".
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