Base | Representation |
---|---|
bin | 10101111110111001… |
… | …01010011011110101 |
3 | 1010110111100110200221 |
4 | 22333130222123311 |
5 | 143132241143233 |
6 | 5231031334341 |
7 | 565314316036 |
oct | 127734523365 |
9 | 33414313627 |
10 | 11801896693 |
11 | 5006954734 |
12 | 23545213b1 |
13 | 11610c2932 |
14 | 7dd5b0a8d |
15 | 49118d42d |
hex | 2bf72a6f5 |
11801896693 has 2 divisors, whose sum is σ = 11801896694. Its totient is φ = 11801896692.
The previous prime is 11801896681. The next prime is 11801896703. The reversal of 11801896693 is 39669810811.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10404408004 + 1397488689 = 102002^2 + 37383^2 .
It is a cyclic number.
It is not a de Polignac number, because 11801896693 - 29 = 11801896181 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11801896693.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11801896793) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5900948346 + 5900948347.
It is an arithmetic number, because the mean of its divisors is an integer number (5900948347).
Almost surely, 211801896693 is an apocalyptic number.
It is an amenable number.
11801896693 is a deficient number, since it is larger than the sum of its proper divisors (1).
11801896693 is an equidigital number, since it uses as much as digits as its factorization.
11801896693 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 559872, while the sum is 52.
The spelling of 11801896693 in words is "eleven billion, eight hundred one million, eight hundred ninety-six thousand, six hundred ninety-three".
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