Base | Representation |
---|---|
bin | 110110111101101100… |
… | …0001000011010101101 |
3 | 102021122222212112001101 |
4 | 1231323120020122231 |
5 | 3413213203243433 |
6 | 130120223043101 |
7 | 11345664535015 |
oct | 1557330103255 |
9 | 367588775041 |
10 | 118034040493 |
11 | 460701586a6 |
12 | 1aa61440491 |
13 | b190acb115 |
14 | 59da1ccc45 |
15 | 310c5b907d |
hex | 1b7b6086ad |
118034040493 has 2 divisors, whose sum is σ = 118034040494. Its totient is φ = 118034040492.
The previous prime is 118034040457. The next prime is 118034040521. The reversal of 118034040493 is 394040430811.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 80337099844 + 37696940649 = 283438^2 + 194157^2 .
It is an emirp because it is prime and its reverse (394040430811) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 118034040493 - 217 = 118033909421 is a prime.
It is a super-3 number, since 3×1180340404933 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (118034041493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59017020246 + 59017020247.
It is an arithmetic number, because the mean of its divisors is an integer number (59017020247).
Almost surely, 2118034040493 is an apocalyptic number.
It is an amenable number.
118034040493 is a deficient number, since it is larger than the sum of its proper divisors (1).
118034040493 is an equidigital number, since it uses as much as digits as its factorization.
118034040493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 37.
The spelling of 118034040493 in words is "one hundred eighteen billion, thirty-four million, forty thousand, four hundred ninety-three".
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