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11805040127 = 82311434217
BaseRepresentation
bin10101111111010001…
…01001110111111111
31010110201021011200102
422333220221313333
5143134042241002
65231222551315
7565353120416
oct127750516777
933421234612
1011805040127
115008701411
12235559853b
13116195365a
147ddb8c47d
154915aea02
hex2bfa29dff

11805040127 has 4 divisors (see below), whose sum is σ = 11806482576. Its totient is φ = 11803597680.

The previous prime is 11805040031. The next prime is 11805040147. The reversal of 11805040127 is 72104050811.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11805040127 - 28 = 11805039871 is a prime.

It is a super-2 number, since 2×118050401272 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11805040127.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11805040147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 708878 + ... + 725339.

It is an arithmetic number, because the mean of its divisors is an integer number (2951620644).

Almost surely, 211805040127 is an apocalyptic number.

11805040127 is a deficient number, since it is larger than the sum of its proper divisors (1442449).

11805040127 is an equidigital number, since it uses as much as digits as its factorization.

11805040127 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1442448.

The product of its (nonzero) digits is 2240, while the sum is 29.

Adding to 11805040127 its reverse (72104050811), we get a palindrome (83909090938).

The spelling of 11805040127 in words is "eleven billion, eight hundred five million, forty thousand, one hundred twenty-seven".

Divisors: 1 8231 1434217 11805040127