Base | Representation |
---|---|
bin | 1010101111011010100100… |
… | …1101110110000110111011 |
3 | 1112210222220120201112121102 |
4 | 2223312221031312012323 |
5 | 3021442233220410312 |
6 | 41041145252002015 |
7 | 2326136322234266 |
oct | 253665115660673 |
9 | 45728816645542 |
10 | 11809704075707 |
11 | 384351608838a |
12 | 13a897200030b |
13 | 67885b989255 |
14 | 2cb84262bcdd |
15 | 1572e68a2ec2 |
hex | abda93761bb |
11809704075707 has 2 divisors, whose sum is σ = 11809704075708. Its totient is φ = 11809704075706.
The previous prime is 11809704075613. The next prime is 11809704075709. The reversal of 11809704075707 is 70757040790811.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11809704075707 - 218 = 11809703813563 is a prime.
It is a super-2 number, since 2×118097040757072 (a number of 27 digits) contains 22 as substring.
Together with 11809704075709, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11809704075709) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5904852037853 + 5904852037854.
It is an arithmetic number, because the mean of its divisors is an integer number (5904852037854).
Almost surely, 211809704075707 is an apocalyptic number.
11809704075707 is a deficient number, since it is larger than the sum of its proper divisors (1).
11809704075707 is an equidigital number, since it uses as much as digits as its factorization.
11809704075707 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3457440, while the sum is 56.
The spelling of 11809704075707 in words is "eleven trillion, eight hundred nine billion, seven hundred four million, seventy-five thousand, seven hundred seven".
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