Base | Representation |
---|---|
bin | 1010101111011111100001… |
… | …1111110100011001111001 |
3 | 1112211010100021120012210220 |
4 | 2223313320133310121321 |
5 | 3022002444222444020 |
6 | 41041525244530253 |
7 | 2326214303060016 |
oct | 253677037643171 |
9 | 45733307505726 |
10 | 11811034187385 |
11 | 3844038981a34 |
12 | 13a9083550989 |
13 | 678a11407c94 |
14 | 2cb92b14a70d |
15 | 157373540240 |
hex | abdf87f4679 |
11811034187385 has 16 divisors (see below), whose sum is σ = 20009281447296. Its totient is φ = 5928675984128.
The previous prime is 11811034187353. The next prime is 11811034187413. The reversal of 11811034187385 is 58378143011811.
It is a cyclic number.
It is not a de Polignac number, because 11811034187385 - 25 = 11811034187353 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23158890309 + ... + 23158890818.
It is an arithmetic number, because the mean of its divisors is an integer number (1250580090456).
Almost surely, 211811034187385 is an apocalyptic number.
11811034187385 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11811034187385 is a deficient number, since it is larger than the sum of its proper divisors (8198247259911).
11811034187385 is a wasteful number, since it uses less digits than its factorization.
11811034187385 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46317781152.
The product of its (nonzero) digits is 645120, while the sum is 51.
The spelling of 11811034187385 in words is "eleven trillion, eight hundred eleven billion, thirty-four million, one hundred eighty-seven thousand, three hundred eighty-five".
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