Base | Representation |
---|---|
bin | 11010110110110001011001… |
… | …111000101001011110000110 |
3 | 120111012111120121211120010122 |
4 | 122312301121320221132012 |
5 | 110440131121304142100 |
6 | 1055112225115021542 |
7 | 33610250640352400 |
oct | 3266613170513606 |
9 | 514174517746118 |
10 | 118113108662150 |
11 | 346a8540701408 |
12 | 112b714113a8b2 |
13 | 50ba031431174 |
14 | 21249c25b3b70 |
15 | d9c5d662a985 |
hex | 6b6c59e29786 |
118113108662150 has 144 divisors (see below), whose sum is σ = 256389836196672. Its totient is φ = 40364228520000.
The previous prime is 118113108662141. The next prime is 118113108662161. The reversal of 118113108662150 is 51266801311811.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 2423753285 + ... + 2423802015.
It is an arithmetic number, because the mean of its divisors is an integer number (1780484973588).
Almost surely, 2118113108662150 is an apocalyptic number.
118113108662150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
118113108662150 is an abundant number, since it is smaller than the sum of its proper divisors (138276727534522).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
118113108662150 is a wasteful number, since it uses less digits than its factorization.
118113108662150 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51955 (or 51943 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 44.
Adding to 118113108662150 its reverse (51266801311811), we get a palindrome (169379909973961).
The spelling of 118113108662150 in words is "one hundred eighteen trillion, one hundred thirteen billion, one hundred eight million, six hundred sixty-two thousand, one hundred fifty".
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