Base | Representation |
---|---|
bin | 10110000000001110… |
… | …01110111110010011 |
3 | 1010111021100102221112 |
4 | 23000013032332103 |
5 | 143143120301103 |
6 | 5232110443535 |
7 | 565511215451 |
oct | 130007167623 |
9 | 33437312845 |
10 | 11813056403 |
11 | 5012187135 |
12 | 23582035ab |
13 | 11634cc305 |
14 | 800c779d1 |
15 | 492144cd8 |
hex | 2c01cef93 |
11813056403 has 2 divisors, whose sum is σ = 11813056404. Its totient is φ = 11813056402.
The previous prime is 11813056369. The next prime is 11813056459. The reversal of 11813056403 is 30465031811.
11813056403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11813056403 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11813056403.
It is not a weakly prime, because it can be changed into another prime (11813056303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5906528201 + 5906528202.
It is an arithmetic number, because the mean of its divisors is an integer number (5906528202).
Almost surely, 211813056403 is an apocalyptic number.
11813056403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11813056403 is an equidigital number, since it uses as much as digits as its factorization.
11813056403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 32.
The spelling of 11813056403 in words is "eleven billion, eight hundred thirteen million, fifty-six thousand, four hundred three".
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