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11813544401 is a prime number
BaseRepresentation
bin10110000000010010…
…00110000111010001
31010111022021020100112
423000021012013101
5143143231410101
65232125131105
7565515320261
oct130011060721
933438236315
1011813544401
11501248a83a
1223583b9a95
131163640479
14800d637a1
154921de6bb
hex2c02461d1

11813544401 has 2 divisors, whose sum is σ = 11813544402. Its totient is φ = 11813544400.

The previous prime is 11813544383. The next prime is 11813544403. The reversal of 11813544401 is 10444531811.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11664216001 + 149328400 = 108001^2 + 12220^2 .

It is a cyclic number.

It is not a de Polignac number, because 11813544401 - 210 = 11813543377 is a prime.

Together with 11813544403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11813544403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5906772200 + 5906772201.

It is an arithmetic number, because the mean of its divisors is an integer number (5906772201).

Almost surely, 211813544401 is an apocalyptic number.

It is an amenable number.

11813544401 is a deficient number, since it is larger than the sum of its proper divisors (1).

11813544401 is an equidigital number, since it uses as much as digits as its factorization.

11813544401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7680, while the sum is 32.

The spelling of 11813544401 in words is "eleven billion, eight hundred thirteen million, five hundred forty-four thousand, four hundred one".