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118173000157 is a prime number
BaseRepresentation
bin110111000001110101…
…0001110000111011101
3102022000200100101212121
41232003222032013131
53414004242001112
6130142105302541
711352302633152
oct1560352160735
9368020311777
10118173000157
114613163a0a3
121aa9ba94a51
13b1b3832a84
145a10842229
1531198b7407
hex1b83a8e1dd

118173000157 has 2 divisors, whose sum is σ = 118173000158. Its totient is φ = 118173000156.

The previous prime is 118173000139. The next prime is 118173000193. The reversal of 118173000157 is 751000371811.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 115745565796 + 2427434361 = 340214^2 + 49269^2 .

It is an emirp because it is prime and its reverse (751000371811) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-118173000157 is a prime.

It is a super-2 number, since 2×1181730001572 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (118173007157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59086500078 + 59086500079.

It is an arithmetic number, because the mean of its divisors is an integer number (59086500079).

Almost surely, 2118173000157 is an apocalyptic number.

It is an amenable number.

118173000157 is a deficient number, since it is larger than the sum of its proper divisors (1).

118173000157 is an equidigital number, since it uses as much as digits as its factorization.

118173000157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5880, while the sum is 34.

Adding to 118173000157 its reverse (751000371811), we get a palindrome (869173371968).

The spelling of 118173000157 in words is "one hundred eighteen billion, one hundred seventy-three million, one hundred fifty-seven", and thus it is an aban number.