Base | Representation |
---|---|
bin | 1010110000011010110010… |
… | …0101010001110101111011 |
3 | 1112212122101210221112012001 |
4 | 2230012230211101311323 |
5 | 3022233033221410301 |
6 | 41053115454401431 |
7 | 2330316415602313 |
oct | 254065445216573 |
9 | 45778353845161 |
10 | 11826940419451 |
11 | 384a8605a2573 |
12 | 13b0182500277 |
13 | 67a377920211 |
14 | 2cc5d9870443 |
15 | 1579a4bb2c01 |
hex | ac1ac951d7b |
11826940419451 has 2 divisors, whose sum is σ = 11826940419452. Its totient is φ = 11826940419450.
The previous prime is 11826940419383. The next prime is 11826940419473. The reversal of 11826940419451 is 15491404962811.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11826940419451 - 29 = 11826940418939 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11826940419392 and 11826940419401.
It is not a weakly prime, because it can be changed into another prime (11826941419451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5913470209725 + 5913470209726.
It is an arithmetic number, because the mean of its divisors is an integer number (5913470209726).
Almost surely, 211826940419451 is an apocalyptic number.
11826940419451 is a deficient number, since it is larger than the sum of its proper divisors (1).
11826940419451 is an equidigital number, since it uses as much as digits as its factorization.
11826940419451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2488320, while the sum is 55.
The spelling of 11826940419451 in words is "eleven trillion, eight hundred twenty-six billion, nine hundred forty million, four hundred nineteen thousand, four hundred fifty-one".
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