Base | Representation |
---|---|
bin | 10110000010010000… |
… | …00011110011001001 |
3 | 1010112110022210202202 |
4 | 23001020003303021 |
5 | 143211443044433 |
6 | 5233515005545 |
7 | 566105523446 |
oct | 130110036311 |
9 | 33473283682 |
10 | 11830049993 |
11 | 5020833723 |
12 | 2361a398b5 |
13 | 1166b9c1a8 |
14 | 80321c9cd |
15 | 49389eee8 |
hex | 2c1203cc9 |
11830049993 has 2 divisors, whose sum is σ = 11830049994. Its totient is φ = 11830049992.
The previous prime is 11830049969. The next prime is 11830050013. The reversal of 11830049993 is 39994003811.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9985605184 + 1844444809 = 99928^2 + 42947^2 .
It is a cyclic number.
It is not a de Polignac number, because 11830049993 - 26 = 11830049929 is a prime.
It is not a weakly prime, because it can be changed into another prime (11830079993) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5915024996 + 5915024997.
It is an arithmetic number, because the mean of its divisors is an integer number (5915024997).
Almost surely, 211830049993 is an apocalyptic number.
It is an amenable number.
11830049993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11830049993 is an equidigital number, since it uses as much as digits as its factorization.
11830049993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 209952, while the sum is 47.
The spelling of 11830049993 in words is "eleven billion, eight hundred thirty million, forty-nine thousand, nine hundred ninety-three".
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