Base | Representation |
---|---|
bin | 10110000011000101… |
… | …00010100011100001 |
3 | 1010112221101111000111 |
4 | 23001202202203201 |
5 | 143220232213323 |
6 | 5234323451321 |
7 | 566221524631 |
oct | 130142424341 |
9 | 33487344014 |
10 | 11836991713 |
11 | 5024745088 |
12 | 2364226b41 |
13 | 116845ca11 |
14 | 8041086c1 |
15 | 4942c1c0d |
hex | 2c18a28e1 |
11836991713 has 2 divisors, whose sum is σ = 11836991714. Its totient is φ = 11836991712.
The previous prime is 11836991701. The next prime is 11836991743. The reversal of 11836991713 is 31719963811.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11812863969 + 24127744 = 108687^2 + 4912^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11836991713 is a prime.
It is a super-2 number, since 2×118369917132 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11836991743) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5918495856 + 5918495857.
It is an arithmetic number, because the mean of its divisors is an integer number (5918495857).
Almost surely, 211836991713 is an apocalyptic number.
It is an amenable number.
11836991713 is a deficient number, since it is larger than the sum of its proper divisors (1).
11836991713 is an equidigital number, since it uses as much as digits as its factorization.
11836991713 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 244944, while the sum is 49.
The spelling of 11836991713 in words is "eleven billion, eight hundred thirty-six million, nine hundred ninety-one thousand, seven hundred thirteen".
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