Base | Representation |
---|---|
bin | 10110000011100001… |
… | …01011011011110011 |
3 | 1010120012100210020001 |
4 | 23001300223123303 |
5 | 143222204314344 |
6 | 5234535130431 |
7 | 566265162466 |
oct | 130160533363 |
9 | 33505323201 |
10 | 11840698099 |
11 | 502684680a |
12 | 2365513a17 |
13 | 1169159a49 |
14 | 8047d12dd |
15 | 4947a4ed4 |
hex | 2c1c2b6f3 |
11840698099 has 2 divisors, whose sum is σ = 11840698100. Its totient is φ = 11840698098.
The previous prime is 11840698097. The next prime is 11840698117. The reversal of 11840698099 is 99089604811.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11840698099 - 21 = 11840698097 is a prime.
It is a super-3 number, since 3×118406980993 (a number of 31 digits) contains 333 as substring.
Together with 11840698097, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11840698091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5920349049 + 5920349050.
It is an arithmetic number, because the mean of its divisors is an integer number (5920349050).
Almost surely, 211840698099 is an apocalyptic number.
11840698099 is a deficient number, since it is larger than the sum of its proper divisors (1).
11840698099 is an equidigital number, since it uses as much as digits as its factorization.
11840698099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1119744, while the sum is 55.
The spelling of 11840698099 in words is "eleven billion, eight hundred forty million, six hundred ninety-eight thousand, ninety-nine".
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