Base | Representation |
---|---|
bin | 1010110010100101101001… |
… | …0000010100010100001011 |
3 | 1120000012121110120110002100 |
4 | 2230221122100110110023 |
5 | 3023340402224223012 |
6 | 41122202234404443 |
7 | 2333106165131415 |
oct | 254513220242413 |
9 | 46005543513070 |
10 | 11864213898507 |
11 | 38646484a0013 |
12 | 13b7445290723 |
13 | 680a37b61779 |
14 | 2d0333ca39b5 |
15 | 1589371268dc |
hex | aca5a41450b |
11864213898507 has 6 divisors (see below), whose sum is σ = 17137197853412. Its totient is φ = 7909475932332.
The previous prime is 11864213898497. The next prime is 11864213898601. The reversal of 11864213898507 is 70589831246811.
11864213898507 is a `hidden beast` number, since 1 + 1 + 8 + 6 + 4 + 2 + 1 + 38 + 98 + 507 = 666.
It is not a de Polignac number, because 11864213898507 - 24 = 11864213898491 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11864213897507) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 659122994353 + ... + 659122994370.
It is a 1-persistent number, because it is pandigital, but 2⋅11864213898507 = 23728427797014 is not.
Almost surely, 211864213898507 is an apocalyptic number.
11864213898507 is a deficient number, since it is larger than the sum of its proper divisors (5272983954905).
11864213898507 is a wasteful number, since it uses less digits than its factorization.
11864213898507 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1318245988729 (or 1318245988726 counting only the distinct ones).
The product of its (nonzero) digits is 23224320, while the sum is 63.
The spelling of 11864213898507 in words is "eleven trillion, eight hundred sixty-four billion, two hundred thirteen million, eight hundred ninety-eight thousand, five hundred seven".
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