Base | Representation |
---|---|
bin | 10110000110110100… |
… | …10110011101101111 |
3 | 1010122010111011100210 |
4 | 23003122112131233 |
5 | 143301302240341 |
6 | 5241404553503 |
7 | 600052505505 |
oct | 130332263557 |
9 | 33563434323 |
10 | 11868399471 |
11 | 5040447205 |
12 | 2372852893 |
13 | 1171b086a6 |
14 | 808362675 |
15 | 496e27c16 |
hex | 2c369676f |
11868399471 has 4 divisors (see below), whose sum is σ = 15824532632. Its totient is φ = 7912266312.
The previous prime is 11868399449. The next prime is 11868399481. The reversal of 11868399471 is 17499386811.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 11868399471 - 26 = 11868399407 is a prime.
It is a super-3 number, since 3×118683994713 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11868399481) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1978066576 + ... + 1978066581.
It is an arithmetic number, because the mean of its divisors is an integer number (3956133158).
Almost surely, 211868399471 is an apocalyptic number.
11868399471 is a deficient number, since it is larger than the sum of its proper divisors (3956133161).
11868399471 is an equidigital number, since it uses as much as digits as its factorization.
11868399471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3956133160.
The product of its digits is 2612736, while the sum is 57.
The spelling of 11868399471 in words is "eleven billion, eight hundred sixty-eight million, three hundred ninety-nine thousand, four hundred seventy-one".
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