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1187599144049 is a prime number
BaseRepresentation
bin10001010010000010011…
…011001101010001110001
311012112101211022100122022
4101102002123031101301
5123424200340102144
62305324151121225
7151541546111033
oct21220233152161
94175354270568
101187599144049
1141872683550a
121721b8673215
1387cb43a2116
14416a15a1c53
1520d5b187cee
hex114826cd471

1187599144049 has 2 divisors, whose sum is σ = 1187599144050. Its totient is φ = 1187599144048.

The previous prime is 1187599143937. The next prime is 1187599144091. The reversal of 1187599144049 is 9404419957811.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 712834047025 + 474765097024 = 844295^2 + 689032^2 .

It is a cyclic number.

It is not a de Polignac number, because 1187599144049 - 216 = 1187599078513 is a prime.

It is a super-2 number, since 2×11875991440492 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1187599143982 and 1187599144000.

It is not a weakly prime, because it can be changed into another prime (1187599104049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 593799572024 + 593799572025.

It is an arithmetic number, because the mean of its divisors is an integer number (593799572025).

Almost surely, 21187599144049 is an apocalyptic number.

It is an amenable number.

1187599144049 is a deficient number, since it is larger than the sum of its proper divisors (1).

1187599144049 is an equidigital number, since it uses as much as digits as its factorization.

1187599144049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13063680, while the sum is 62.

The spelling of 1187599144049 in words is "one trillion, one hundred eighty-seven billion, five hundred ninety-nine million, one hundred forty-four thousand, forty-nine".