Base | Representation |
---|---|
bin | 10110001001110010… |
… | …01001110100011001 |
3 | 1010200212020202201212 |
4 | 23010321021310121 |
5 | 143324133020403 |
6 | 5244053352505 |
7 | 600503653124 |
oct | 130471116431 |
9 | 33625222655 |
10 | 11893251353 |
11 | 5053480855 |
12 | 237b038735 |
13 | 1176cca349 |
14 | 80b7913bb |
15 | 4991d64d8 |
hex | 2c4e49d19 |
11893251353 has 2 divisors, whose sum is σ = 11893251354. Its totient is φ = 11893251352.
The previous prime is 11893251317. The next prime is 11893251389. The reversal of 11893251353 is 35315239811.
It is a balanced prime because it is at equal distance from previous prime (11893251317) and next prime (11893251389).
It can be written as a sum of positive squares in only one way, i.e., 10816624009 + 1076627344 = 104003^2 + 32812^2 .
It is a cyclic number.
It is not a de Polignac number, because 11893251353 - 216 = 11893185817 is a prime.
It is a super-3 number, since 3×118932513533 (a number of 31 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11893251353.
It is not a weakly prime, because it can be changed into another prime (11893251553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5946625676 + 5946625677.
It is an arithmetic number, because the mean of its divisors is an integer number (5946625677).
Almost surely, 211893251353 is an apocalyptic number.
It is an amenable number.
11893251353 is a deficient number, since it is larger than the sum of its proper divisors (1).
11893251353 is an equidigital number, since it uses as much as digits as its factorization.
11893251353 is an evil number, because the sum of its binary digits is even.
The product of its digits is 97200, while the sum is 41.
The spelling of 11893251353 in words is "eleven billion, eight hundred ninety-three million, two hundred fifty-one thousand, three hundred fifty-three".
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